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Mathematics 18 Online
OpenStudy (anonymous):

Definite Integral Question!!!!

OpenStudy (anonymous):

\[\Large \int\limits_{0}^{\pi/4}xtanx~dx\]

geerky42 (geerky42):

I don't think it is possible to take integral and have it expressed in elementary algebra...

OpenStudy (anonymous):

I'm sure if my teacher wants me to show work cause i try to look up the indefintie integral of this and it's this big ol formula

OpenStudy (anonymous):

I'm not sure

OpenStudy (mathmale):

If I were you I'd make a list of the various methods of integration for reference and look at it often. The first impression I got here was that this particular definite integral would be a perfect candidate for integration by parts. But don't take my word for it; try integration by parts and see if you can make this method work for you.

OpenStudy (anonymous):

I'm in Calc AB so we haven't learned Integration by parts which is why I want to know how to do it without that method.

OpenStudy (mathmale):

Which other methods have you considered, have you tried, have you eliminated? Have you considered numerical integration?

OpenStudy (anonymous):

I think my teacher wanted me to just my calculator cause I don't have any rules from this list that I'm supposed to use to calculate

OpenStudy (anonymous):

It's fine, haha

geerky42 (geerky42):

so you can use calculator? what kind? like I said, integral of x tanx cannot be expressed in elementary algebra. this problem shouldn't be given to you.

OpenStudy (mathmale):

Have you studied Riemann Sums? Have you considered using either the Trapezoidal Rule or Simpson's Rule?

OpenStudy (mathmale):

Have you learned how to express functions such as tan x as series?

OpenStudy (anonymous):

OpenStudy (mathmale):

Have you learned how to use integration rule #10?

geerky42 (geerky42):

It's \(\int xtan(x) dx \), not \(\int tan(x) dx\) there is really no product rule for integral. though it is possible to solve with Riemann Sums

geerky42 (geerky42):

yeah, Riemann Sums should be used. do you know that method? @doulikepiecauseidont

OpenStudy (anonymous):

Yes, but can you catch me up on it again?

OpenStudy (anonymous):

We pick a number of intervals, lets just say n=4 and we split up the interval [0,pi/4] innto those intervals of \[\Large \Delta x =\frac{ \frac{ \pi }{ 4 } -0}{ 4 }\]

OpenStudy (anonymous):

\[\Large \Delta x=\frac{ \pi }{ 16} \]

OpenStudy (mathmale):

And then your x values would be \[x _{i}=a+i*\Delta x=0+i*\Delta x =i*\Delta x\]

OpenStudy (anonymous):

\[\Large \frac{ \pi }{ 16 }(f(\frac{ \pi }{ 4 })+f(\frac{ 3\pi }{ 16 })+f(\frac{ \pi }{ 8 })+f(\frac{ \pi }{ 16 }))\]

OpenStudy (anonymous):

Is that the correct set up (using a right hand Riemann sum of n=4 intervals)?

OpenStudy (mathmale):

and your function, f(x) = x*tan x would then become\[(i*\Delta x)\tan(i*\Delta x)\] which would be easy to do with a calculator or computer but NOT with the methods you already have.

OpenStudy (anonymous):

But is that set up correct?

OpenStudy (mathmale):

My \[x _{i}=a+i*\Delta x=0+i*\Delta x =i*\Delta x\] DOES assume that we are using the right end point. You would be summing up terms that resemble the following:\[(i*\Delta x)\tan(i*\Delta x)*\Delta x\]

OpenStudy (anonymous):

OK, thanks!

OpenStudy (mathmale):

Please note that delta x in the Riemann sums method is not a constant such as Pi/12; it's a function of n, where n is the number of subdivisions of your integral. If y ou arbitrarily choose n=4, you are using numerical approximation to evaluate your integral, and not Riemann Sums.

OpenStudy (anonymous):

Ok,

OpenStudy (mathmale):

You might want to refer to the following: https://answers.yahoo.com/question/index?qid=20100125030601AA3vO51 before you invest any more time and effort into this problem.

OpenStudy (mathmale):

Nothing wrong with using numerical methods / numerical approximations, so long as y ou undrstand that this is not the same thing as Riemann Sums, and that your result via choosing n = 4, n=10, and so on, will ONLY be approximations. On the other hand, if you apply Riemann Sums to integrate a simple polynomial function, your result will the the EXACT area under your curve from x=a to x=b. Good luck! I need to get off the Internet now.

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