Question

Calculate the area of triangle ABC with altitude CD, given A (−3, −4), B (−6, 2), C (0, 0), and D (−4, −2).
A. 14 square units
B. 15 square units
C. 18 square units
D. 20 square units

Answer 1

Use the distance formula which is: \[\sqrt{(x _{1}-x _{2})^{2} \times (y _{1}-y _{2})^{2}}\]

Answer 2

I'm not sure I understand....Where does the plot points come in? @irockout

Answer 3

Ok so for example, if you were trying to find the base of the triangle (which is AB I believe) you would do: \[\sqrt{(-3--6)^{2}+ (-4-2)^{2}}\]

Answer 4

So, for the problem i'm doing, CD, I'd do. \[\sqrt{(0 - -4)^{2} + (0 - -2)} \]

Answer 5

yes except you also have to square the (0--2)

Answer 6

so, \[\sqrt{(4^2 + 2^2}\]

Answer 7

\[\sqrt{ 16 + 4}\]

Answer 8

yes

Answer 9

\[\sqrt{20} = 4 ??\]

Answer 10

\[\sqrt{20} = 2\sqrt{5}\]

Answer 11

4.47...

Answer 12

But that's not one of the answers. @irockout

Answer 13

are you sure your coordinates are correct?

Answer 14

Yes. I'm positive.