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Mathematics 14 Online
OpenStudy (anonymous):

If sin Θ = 2 over 3 and tan Θ < 0, what is the value of cos Θ? square root 5 over 2 negative square root of 5 square root of 5 over 3 negative square root of 5 over 3

OpenStudy (anonymous):

@hartnn can you help me with this triq question?

OpenStudy (anonymous):

uhh... i can't spell.. >.< its trig, not triq haha

OpenStudy (noelgreco):

First, figure out the quadrant in which sin is + and tan is -

OpenStudy (anonymous):

tan is - in quadrants II and IV and sin is + in quadrants I and II

OpenStudy (anonymous):

ok, since tan(theta) is negative, and sin(theta) is postive, what can you tell about cos(theta)? (Remember that tan = sin/cos).

OpenStudy (anonymous):

so it has to be negative, right?

OpenStudy (anonymous):

oh, so would i convert the "tan = sin/cos" to solve for cos?

OpenStudy (anonymous):

well... you can't really "solve" for cos because you were not given a number for tan. You can however, figure out the position of sin in the unit circle. What are the possible numbers for sin?

OpenStudy (anonymous):

ahh, ok uh so 2/3 is sin ...

hartnn (hartnn):

use, \(\Large \sin^2 x+\cos^2 x=1\)

OpenStudy (anonymous):

what is x?

hartnn (hartnn):

and you have correctly determined that cos should be negative because tan = sin / cos for than to be negative since sin is positive, cos must be negative

hartnn (hartnn):

x is the angle here, its theta

hartnn (hartnn):

\(\sin \theta = 2/3 \\ \cos\theta = \sqrt{1-\sin^2 \theta}=...\)

OpenStudy (anonymous):

Please use the Pythagorean theorem to find the value of cos from the given value of sin. For this first draw a triangle |dw:1399750906685:dw| Now by Pythagorean theorem the other side is equal to sqrt(9 - 4) = sqrt(5). cos(theta) = adjacent / hypotenuse = sqrt(5) / 3. Can you do it from here?

hartnn (hartnn):

oh, and thats an alternative method, the triangle to solve the same problem ^^

OpenStudy (anonymous):

so which one should I use?

hartnn (hartnn):

well, look at both, use the one which u find easy. but its better if you know both....maybe you can use both to verify your answer

hartnn (hartnn):

i mean use one to find the answer and other to verify it

OpenStudy (anonymous):

ok, makes sense... so I'll start with the equation... i guess

hartnn (hartnn):

sure tell us what you got for cos

OpenStudy (anonymous):

ok, so... is x necessarily equal to something?

hartnn (hartnn):

x is an angle, like theta \(\sin^2 \theta +\cos^2 \theta =1\) better ? you know sin theta, find cos theta from there,,,

hartnn (hartnn):

\(\Large (2/3)^2 + \cos^2 \theta =1 \)

OpenStudy (anonymous):

uhm, so I tried to solve, and I got 139/250 .... ? it doesn't sound right to me.....

hartnn (hartnn):

how... \(\cos^2 \theta = 1- 4/9 = 5/9\) take square root now

OpenStudy (anonymous):

>.< for how: that's what my calculator says... O.o the square root of 5/9... right? ok, so I got 0.745 ...

OpenStudy (anonymous):

Don't use a calculator for such calculations. Square root of 5/9 is sqrt(5) over sqrt(9), which gives you sqrt(5)/3 Thus cos(theta) = sqrt(5)/3 and that is your answer

hartnn (hartnn):

no need of calculator, i guess u know, square root of 9 is 3 \(\cos^2 \theta = 5/9 \\ \cos \theta = \sqrt{(5/9)}= \sqrt5 /\sqrt 9 = \sqrt 5/3\) and don't forget to add a negativee sign

hartnn (hartnn):

so, actually, cos theta = - sqrt 5/3

OpenStudy (anonymous):

oh, ok so i don't have to simplify it to a solid number ?

hartnn (hartnn):

look at your choices

OpenStudy (anonymous):

ohhhhh wait.... no >.< okay then haha hartnn: yup, just looked at them.....

hartnn (hartnn):

ok, ask if any more doubts on this :)

OpenStudy (anonymous):

soo, if I use the other method...

hartnn (hartnn):

did you get how he got that triangle ? the 2 sides on it ?

hartnn (hartnn):

because getting 3rd side is easy, a pythagoras theorem.

OpenStudy (anonymous):

hmm ..... did he get the values of the 2 sides from the 2/3 ?

hartnn (hartnn):

yes since sin = opposite side/ hypotenuse = 2/3 he too opposite side = 2 hypotenuse = 3 makes sense ? thats what u do always

hartnn (hartnn):

he took*

OpenStudy (anonymous):

OHH!! I Just got it! ok!

OpenStudy (anonymous):

yes it make sense, thank you so so much! :D

hartnn (hartnn):

welcome ^_^

OpenStudy (anonymous):

Ahem. Provide a solution or counter example. LOL xD

OpenStudy (anonymous):

O.o

OpenStudy (anonymous):

|dw:1399667441214:dw||dw:1399667461494:dw|

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