If sin Θ = 2 over 3 and tan Θ < 0, what is the value of cos Θ? square root 5 over 2 negative square root of 5 square root of 5 over 3 negative square root of 5 over 3
@hartnn can you help me with this triq question?
uhh... i can't spell.. >.< its trig, not triq haha
First, figure out the quadrant in which sin is + and tan is -
tan is - in quadrants II and IV and sin is + in quadrants I and II
ok, since tan(theta) is negative, and sin(theta) is postive, what can you tell about cos(theta)? (Remember that tan = sin/cos).
so it has to be negative, right?
oh, so would i convert the "tan = sin/cos" to solve for cos?
well... you can't really "solve" for cos because you were not given a number for tan. You can however, figure out the position of sin in the unit circle. What are the possible numbers for sin?
ahh, ok uh so 2/3 is sin ...
use, \(\Large \sin^2 x+\cos^2 x=1\)
what is x?
and you have correctly determined that cos should be negative because tan = sin / cos for than to be negative since sin is positive, cos must be negative
x is the angle here, its theta
\(\sin \theta = 2/3 \\ \cos\theta = \sqrt{1-\sin^2 \theta}=...\)
Please use the Pythagorean theorem to find the value of cos from the given value of sin. For this first draw a triangle |dw:1399750906685:dw| Now by Pythagorean theorem the other side is equal to sqrt(9 - 4) = sqrt(5). cos(theta) = adjacent / hypotenuse = sqrt(5) / 3. Can you do it from here?
oh, and thats an alternative method, the triangle to solve the same problem ^^
so which one should I use?
well, look at both, use the one which u find easy. but its better if you know both....maybe you can use both to verify your answer
i mean use one to find the answer and other to verify it
ok, makes sense... so I'll start with the equation... i guess
sure tell us what you got for cos
ok, so... is x necessarily equal to something?
x is an angle, like theta \(\sin^2 \theta +\cos^2 \theta =1\) better ? you know sin theta, find cos theta from there,,,
\(\Large (2/3)^2 + \cos^2 \theta =1 \)
uhm, so I tried to solve, and I got 139/250 .... ? it doesn't sound right to me.....
how... \(\cos^2 \theta = 1- 4/9 = 5/9\) take square root now
>.< for how: that's what my calculator says... O.o the square root of 5/9... right? ok, so I got 0.745 ...
Don't use a calculator for such calculations. Square root of 5/9 is sqrt(5) over sqrt(9), which gives you sqrt(5)/3 Thus cos(theta) = sqrt(5)/3 and that is your answer
no need of calculator, i guess u know, square root of 9 is 3 \(\cos^2 \theta = 5/9 \\ \cos \theta = \sqrt{(5/9)}= \sqrt5 /\sqrt 9 = \sqrt 5/3\) and don't forget to add a negativee sign
so, actually, cos theta = - sqrt 5/3
oh, ok so i don't have to simplify it to a solid number ?
look at your choices
ohhhhh wait.... no >.< okay then haha hartnn: yup, just looked at them.....
ok, ask if any more doubts on this :)
soo, if I use the other method...
did you get how he got that triangle ? the 2 sides on it ?
because getting 3rd side is easy, a pythagoras theorem.
hmm ..... did he get the values of the 2 sides from the 2/3 ?
yes since sin = opposite side/ hypotenuse = 2/3 he too opposite side = 2 hypotenuse = 3 makes sense ? thats what u do always
he took*
OHH!! I Just got it! ok!
yes it make sense, thank you so so much! :D
welcome ^_^
Ahem. Provide a solution or counter example. LOL xD
O.o
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