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OpenStudy (anonymous):
@mathslover if you have time?
OpenStudy (anonymous):
I answered 160
mathslover (mathslover):
How did you get 160?
OpenStudy (anonymous):
I forgot how but I think I counted two for every possible out of 20 people. If that made sense?
OpenStudy (anonymous):
actually I recounted it would be 40 right?
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mathslover (mathslover):
No need to count actually. I think, it is 380 but I am not sure.
mathslover (mathslover):
@KingGeorge - Can you please confirm it?
I did like this :
\(\cfrac{20!}{(20-2)!} = \cfrac{20!}{18!} = 20 \times 19 = 380\)
OpenStudy (anonymous):
Ok i'm writing it down. Thanks
mathslover (mathslover):
Bison, am not sure yet. Wait for KG's response please.
OpenStudy (anonymous):
k
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OpenStudy (kinggeorge):
@mathslover is correct.
An alternative way to look at it would be to say that you have 20 choices for the captain, and 19 for the co-captain, so there are \(20*19\) choices total.
mathslover (mathslover):
Oh I feel better now :) Thanks @KingGeorge
OpenStudy (anonymous):
awesome! Thanks guys!!
mathslover (mathslover):
You're welcome :)
OpenStudy (kinggeorge):
No problem.
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OpenStudy (anonymous):
I don't feel we do enough probability. So when it comes time to do the work I am not entirely clear on it all. Thankful for you guys here at Open Study!