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@Cydney_Morgan
kk, so if it reflects on the x-axis, then what's the y-int now?
i think D
@alias
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nope. Ok here's how you know. What direction is the end point? Up or down?
Then because of the reflection, the end points should now point in the opposite direction, right? So your function has to be negative. The y-int of the original function (0,3) has to be reflected too. So if the reflection happens in the x-axis, what would this point now be?
B
not quite, the intercept would have to be (0,-3), so the answer is A
ty @alias
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