Tom wants to hang a mirror in his room. The mirror and frame must have an area of 14 square feet. The mirror is 3 feet wide and 4 feet long. Which quadratic equation can be used to determine the thickness of the frame, x?
A = L x W (mirror and frame) do we assume uniform thickness of frame?
Yes.
\[14 = (L) \times (W)\] \[14 = (Mirror L + Frame L) \times (Mirror W + Frame W)\] \[14 = (4 + x) \times (3 + x)~~\text{if uniform thickness}\] \[\text{use FOIL to expand}~~(4 + x) (3 + x)~~\] can u solve from here @BasedGod1122 ???
12+4x+3x+x^2 ?
yep, that's ur quadratic, and that = 14
no, that equals 14, if u take 14 from both sides, u can find the zero's...
x^2 + 7x - 2 = 0 solve for x to find thickness
How do I solve for x? Walk me through the steps?
x = 0.27491721763537484861834240347306 feet
do you know the quadratic equation...?
This is a multiple choice question. My choices are: 4x2 + 14x - 2 = 0 3x2 + 10x - 14 = 0 2x2 + 12x - 14 = 0 x2 + 7x - 14 = 0
use the formula \[\frac{ -b +- \sqrt{b ^{2}-4ac} } {2}\]
none of the above options work, as @kx2bay said, the quadratic equation comes down to x^2 + 7x - 2 = 0 so non of ur answers match...?
yes jack is right if you substitute x = 0.27492 in jacks formula above 14=(4+x)×(3+x) u get 14=14
So which choice do i select
none of the above choices is correct, I'd say they made a typo with the 4th choice x2 + 7x - 14 = 0 where -14 should be -2 so go with this choice
Thank you, friend. You've really helped me out. I hope that you have a good night.
thanks you too, its actually day light here in melbourne australia ;)
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