Question

Factor x^2 + 2root3x + 3

Answer 1

\[x^2+2\sqrt{3x}+3?\]

Answer 2

Yes

Answer 3

=?

Answer 4

It just needs to be factored it comes from getting the square of 9x^2 + 18root3x. I took the nine out and ended up with the equation above.

Answer 5

\[x^2+2\sqrt{3}\sqrt{x}+3\]

Answer 6

You can't do much with it.

Answer 7

That is what I was thinking. It comes from a problem dealing with ellipses

Answer 8

Is the expression like this: x^2 + 2sqrt(3)x + 3 ? The x is outside or inside the square root?

Answer 9

The equation is like that. The x is inside the squareroot. Iambatman wrote it out correctly on the first comment.

Answer 10

did u start with
\[9x^{2} + 18\sqrt{3}x + 27 \]

Answer 11

Then it can't be factored but you can complete its square.

Answer 12

No. I started out with just the first two terms of the equation you wrote above and had to complete the square for the equation. and that is what I got

Answer 13

Even completing the square will not work if the x is inside the square root

Answer 14

Oh? How so?

Answer 15

it will help if you type your original problem (before doing the completing the square) properly, perhaps draw it or use the formula/equation editor or write it on a piece of paper take a picture of it and attach it here

Answer 16

Because a complete square is of the form (a + b)^2 = a^2 + 2ab + b^2. That is, you need to have an 'a^2' and a '2ab' term in order to complete the square. Here you have x^2 in the form of a^2 but not 2ab because you have 2sqrt(3x), and it does not have an x without the square root.

Answer 17

Oh okay. Thank you

Answer 18

navk i think she meant to write this
\[9x ^{2} + 18\sqrt{3} * x\]

jess correct me if am wrong

Answer 19

Yes I did. I just relooked at my problem and the x is not covered by the squareroot sign. Kx2bay you are right

Answer 20

That greatly simplifies it. Now you can =factor it as follows:
x^2 + sqrt(3)x + sqrt(3)x + 3
x(x + sqrt(3)) + sqrt(3)(x + sqrt(2))
(x + sqrt(3))^2

Answer 21

jess will the answer be this