sin 8 theta
What is your question(s)?
I ned to find a formula for sin8 theta
What you are asking is vague, I am still not sure what your question is.
\[\sin(8\theta)\]
using the double angle formula, i am asked to find a formula for \[\sin (8\theta)\]
Do you know the double-angle formula?
yes, \[\sin (2\theta)=2\sin \theta \cos \theta \]
What must you do then so that your original trigonometric function matches that of the Sine double-angle identity?
\[\sin 4(2\theta)\] I don't understand beyond that.
Lets break down the identity
\[\sin(2\theta)=2\sin(\theta)\cos(\theta) \] Do you notice what happens to the \[(2\theta)\] as it goes to the identity?
it gets broken into the 2 sine theta and cosine theta?
Yes but more specifically what happens to just the theta?
Hint: \[(2\theta) \] is really \[(2 \times \theta) \]
i have no idea. this a new concept for me so i have no clue
Lets look at just the sine on the left and right, what is missing from the theta after it goes into the identity?
the 2 next to theta
Right! More specifically the theta lost a multiple of 2 to become the identity on the right. So after analyzing the identity, what must \[\sin(8\theta) \] do to have a 2 next to it?
be \[\sin 4(2\theta)\]?
No for the identity we only lost a multiple of 2 not a multiple of 4 so to use that identity what must it lose?
a 2?
Correct! Awesome so what would our new identity look like on the left if it only lost a multiple of 2?
Hint:\[\sin(8\theta)=2\sin(?)\cos(?)\]
\[\sin (8\theta)=2\sin (\theta)\cos(\theta)\]
That is still incorrect. The multiple of only 2 was removed from the original \[(8\theta)\] so it can not be only \[2\sin(\theta)\cos(\theta)\] there must be something missing within the \[(?\theta)\] what do you think it is?
2
If we say that 2 is the missing variable and multiply the multiple of 2 back into the \[(\theta)\] it will give us \[2 \times (2\theta) = (4\theta)\] which is not our original theta so what must be the missing variable?
4?
Correct! Because we have to be consistent with our identity\[2 \sin(\theta)\cos(\theta)\] then the original function can only lose the multiple of 2 as shown which by simply algebra shows that \[2 \times ? = 8\]
Now that we know the missing variable is 4 by analyzing the identity what must our anwser be?
i have no idea what to do next
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