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OpenStudy (anonymous):
how many atoms of hydrogen are present in 25g of NH4Cl
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OpenStudy (anonymous):
1 mole of NH4Cl = 14+4+35.5= 53.5 g 1 mole of NH4Cl = 4 moles of H 53.5 g of NH4Cl = 4 g of H 25 g of NH4Cl = 4/53.5 X 25 = 1.86 g of H
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