Question

Another conversion from polar to rectangular form.
r=4/(1+2sin(theta))
would that become 3y^2=x^2?

Answer 1

16-16y those terms ??

Answer 2

@ddd231 - rather than just listing what you believe to be the answer it would be better if you listed your steps so we can help spot where you may have made a mistake

Answer 3

\[\sin \theta = \frac{y}{r}\]
\[r (1 + \frac{2y}{r}) = 4\]
\[r = 4 - 2y\]
\[r^2 = 16 -16y +4y^2\]
\[x^2 +y^2 = 16 -16y +4y^2\]
\[x^2 = 3y^2 -16y +16\]

Answer 4

i see what i did wrong now. when i multiplied over the 1+2sintheta i made the 4 into a 1

Answer 5

Thanks for the answer @dumbcow and thanks d=for the help and you time as well @asnaseer @sidsiddhartha next time ill write out what i did

Answer 6

yw :)

Answer 7

wlcm:)