Question

Assume the triangle has the given measurements. Solve for the remaining sides and angles

a) C=100°, a=(1/2),b=(1/3)
b) A=(π/6,a=17.4,b=19.6

Answer 1

@Jack1

Answer 2

so do u recon for (a) we use sine rule or cosine rule...?

Answer 3

cosine

Answer 4

coolski, me to

so \(\large c^2 = a^2 + b^2 - 2ab(\cos (C))\)
solve for c
= ...? @washcaps ?

Answer 5

ok hold on

Answer 6

then use Sine rule to solve for other angles... easier that way ;)

Answer 7

c=.65

Answer 8

i'll just work it out too, sorry man, 1 sec

Answer 9

0.647... so 0.65, so perfect man

Answer 10

now use sine rule to work out other angles

Answer 11

so sinB/1/3? sinA/1/2?

Answer 12

\[\Large \frac a{\sin A} = \frac c{\sin C}\]... solve for A first.. then do the same for B

Answer 13

ah, ur way is easier solving for angle, sorry man

Answer 14

\[\Large \frac {\sin A}a = \frac {\sin C}c\]

Answer 15

my calculator is screwing up. I know the equation is sinA/1/2 = sin(100)/0.65. Could you solve?

Answer 16

sure sin (100)/0.647297 = 1.52142 = Sin A/0.5
so Sin A = 0.76071
so A = 49.52 degrees

Answer 17

180 - 100 - 49.52 = B = 30.48 ish...?

Answer 18

real quick this website http://www.calculatorsoup.com/calculators/geometry-plane/triangle-law-of-sines.php says that A=49.24?

Answer 19

maybe i rounded too early...?

Answer 20

oh ok so what would be the right answer? the website or yours?

Answer 21

maybe u used 0.65 instead of 0.647297 on the website...?

Answer 22

oh I did sorry. Yours is correct then

Answer 23

cools ;) either way they're both pretty close

Answer 24

k, u got this man, imma finish my assignment, slaters ;)

Answer 25

Thanks. I could use your help later tonight if your on haha :)

Answer 26

prob not, its 3:30 am here, will be sleepin like the dead tomorro night ;)

Answer 27

not on this. different question lol oh ok man thanks though

Answer 28

sorry man :(

Answer 29

np night