Find the smallest real zero for f(x) = x^3 + 7x^2 + 4x + 28
First you need to find all the zeros, if you're going to compare them and choose the smallest real zero. Have you considered how you'd find the zeros of f(x) = x^3 + 7x^2 + 4x + 28? I'd use synthetic division myself, but there are other ways as well. Hint: What are some of the integer factors of 28, whether positive or negative?
the zeroes are 2i,-2i, and -7
Let's verify that -7 is a zero: -7 | 1 7 4 28 -7 0 -28 ---------------------- 1 0 4 0 since there is no remainder, yes, -7 is a root. You say that the three zeros are -7, 2i, and -2i From these three zeros, please choose the smallest real zero.
-7?
Right. That's the only real zero, so is the only possible answer.
thank you
Join our real-time social learning platform and learn together with your friends!