Ask your own question, for FREE!
Mathematics 19 Online
OpenStudy (anonymous):

Find the smallest real zero for f(x) = x^3 + 7x^2 + 4x + 28

OpenStudy (mathmale):

First you need to find all the zeros, if you're going to compare them and choose the smallest real zero. Have you considered how you'd find the zeros of f(x) = x^3 + 7x^2 + 4x + 28? I'd use synthetic division myself, but there are other ways as well. Hint: What are some of the integer factors of 28, whether positive or negative?

OpenStudy (anonymous):

the zeroes are 2i,-2i, and -7

OpenStudy (mathmale):

Let's verify that -7 is a zero: -7 | 1 7 4 28 -7 0 -28 ---------------------- 1 0 4 0 since there is no remainder, yes, -7 is a root. You say that the three zeros are -7, 2i, and -2i From these three zeros, please choose the smallest real zero.

OpenStudy (anonymous):

-7?

OpenStudy (mathmale):

Right. That's the only real zero, so is the only possible answer.

OpenStudy (anonymous):

thank you

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!