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Mathematics 6 Online
OpenStudy (anonymous):

Decide whether x = −1, x = −3 are zeros of f(x) = x^4 + 3x^3 + 2x^2 + 6x + 3 1. Only x = −3 2. Both are zeros 3. Only x = −1 4. Neither is a zero

OpenStudy (mathmale):

Enjoyed working with you on the previous problem. In this one, why not use synthetic division again to determine whether either -1 or -3 is a root of the given polynomial? -1 | 1 3 2 6 3 ? -------------- 1

OpenStudy (anonymous):

how do I determine that?

OpenStudy (mathmale):

Have you had any introduction to synthetic division, or any practice with it?

OpenStudy (anonymous):

no

OpenStudy (mathmale):

Have you had any introduction to long division, or any practice with it?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

plug in the values x = -1 and x = -3 into f(x) and see if you get 0...

OpenStudy (anonymous):

for -1 I don't get 0

OpenStudy (anonymous):

then x = -1 is not a zero...what about -3?

OpenStudy (anonymous):

i get neither zero?

OpenStudy (anonymous):

is that correct?

OpenStudy (anonymous):

i agree :) do you understand *what* a "zero" of a polynomial is?

OpenStudy (anonymous):

yes its the intercept right?

OpenStudy (anonymous):

x intercept*

OpenStudy (anonymous):

sort of...if you're talking about the graph...more specifically, a "zero" of a polynomial is any x-value that makes the polnomial = 0. they are important because when we want to graph the polynomial, the zeros tell us where it touches (or crosses) the x-axis. in calculus, they also tell us other things like if the graph is opening up, or down...among other things. but at the heart of it, if you see the "zero" of a polynomial, really you are just checking (or finding) those values...plugging in is the easiest test method.

OpenStudy (anonymous):

mathmale mentioned synthetic division which you will eventually cover...it's useful in finding the zeros because each time you find one, the problem gets easier...

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