Decide whether x = −1, x = −3 are zeros of f(x) = x^4 + 3x^3 + 2x^2 + 6x + 3 1. Only x = −3 2. Both are zeros 3. Only x = −1 4. Neither is a zero
Enjoyed working with you on the previous problem. In this one, why not use synthetic division again to determine whether either -1 or -3 is a root of the given polynomial? -1 | 1 3 2 6 3 ? -------------- 1
how do I determine that?
Have you had any introduction to synthetic division, or any practice with it?
no
Have you had any introduction to long division, or any practice with it?
no
plug in the values x = -1 and x = -3 into f(x) and see if you get 0...
for -1 I don't get 0
then x = -1 is not a zero...what about -3?
i get neither zero?
is that correct?
i agree :) do you understand *what* a "zero" of a polynomial is?
yes its the intercept right?
x intercept*
sort of...if you're talking about the graph...more specifically, a "zero" of a polynomial is any x-value that makes the polnomial = 0. they are important because when we want to graph the polynomial, the zeros tell us where it touches (or crosses) the x-axis. in calculus, they also tell us other things like if the graph is opening up, or down...among other things. but at the heart of it, if you see the "zero" of a polynomial, really you are just checking (or finding) those values...plugging in is the easiest test method.
mathmale mentioned synthetic division which you will eventually cover...it's useful in finding the zeros because each time you find one, the problem gets easier...
Join our real-time social learning platform and learn together with your friends!