Question

How do I find the empirical formula, and name of the compound for cation and anion ionic compounds?

Answer 1

lets say you have glucose C6H12O6 first you would have to find what they are all divisible by which is 6 so you divide by 6 giving you CH6O

Answer 2

They are only giving me the cation and anion to find these things no the formula. Like Pb^2+ and \[PO _{4}^{3-}\] for the first line and Cr^2+ and \[C _{2}H _{3}O _{2}^{-}\] for the second line and Na+ and \[NO _{2}^{-}\].

Answer 3

you need the name of these compounds?

Answer 4

yes and the empirical formula.

Answer 5

okay the first one is lead (Roman numeral 2) phosphate Pb3(PO4)2 empirical formula is im not to sure if you would divide the 4 by 2 making it Pb3(PO2) or leave it as it is.

Answer 6

2) Calcium Acetate C(C2H302)2 once again im not sure about the EF but i would divde by 2 making it C(CH3O)

Answer 7

do you get it ??

Answer 8

I think it is the first one on both. Pb3(PO4)2 and Ca(C₂H₃O₂)₂

Answer 9

On the second line how did you get Ca when it starts with Cr?

Answer 10

sorry i ment Cr

Answer 11

So it wound't be Calcium then because Ca is Calcium, right?

Answer 12

no its not calcium

Answer 13

yes Ca is calcium

Answer 14

Is it Chromium (II) Acetate or Chromium (III) Acetate?

Answer 15

Chromium (II) Acetate

Answer 16

you think you can do the last one ?

Answer 17

I think so

Answer 18

I think it is Sodium Nitrate but am unsure is it NaNO3 or NaNO^3?

Answer 19

where did you get three from ?

Answer 20

If it is not 3 than it is a 2 and it is nitrite.

Answer 21

yes it is 2 NaNO2

Answer 22

and yes your right its sodium nitrite