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Compute the following integral ∫ 6^(x) /4^(x-1) dx ?
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\[\int\limits \frac{ 6^x }{ 4^{x-1} }dx=\int\limits \frac{ 6^x }{ 4^x*4^{-1}}dx=4 \int\limits \left( \frac{ 6 }{ 4 } \right)^x dx=?\] \[\int\limits a^x dx=\frac{ a^x }{ \log a }\]
4 integral (3/2)^x / ln(3/4) + C @surjithayer I'm cofused as to what happens to the 4 outside the integral, could you please explain ?
you are mistaken. \[4 \int\limits \left( \frac{ 3 }{ 2 } \right)^xdx=4 \frac{ \left( \frac{ 3 }{ 2 } \right)^x }{ \ln \left( \frac{ 3 }{ 2 } \right)}+c\]
Oh okay thank you for explaining !
yw
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