Question

need help with graphhs please anyone

Answer 1

@kirbykirby

Answer 2

does the graph of \(y=x^2+7x+7\) open up or down?

Answer 3

down :s

Answer 4

the \(x^2\) has a positive constant in front of it (namely \(1\)). Since it's positive, the parabola must open up.

Answer 5

Once you know that, and how to graph the equation of the given line, only one solution will be possible :)

Answer 6

Actually just knowing how to graph the equation of the line in this problem will give you only one answer lol.

Answer 7

hmm C

Answer 8

am i wrong? @kirbykirby :(

Answer 9

no that's right :)

Answer 10

really !! yayy! :D

Answer 11

can you help me with another

Answer 12

sure

Answer 13

The easiest way to do this would be to take the first x value, -2, and plug it into the equation of a), and verify if it equals -7 (the y value)

Then do the same for the next x-value, 0, and see if it gives 3 (the y-value) once you plug it in.

But doing this blindly for every answer might be long. So an easy shortcut is to look at the x=0 value (the 2nd column). Since this is very easy to evaluate, it should give y=3 in the column, so look at the answers that have a +3 as the constant term (since the x's disappear as x=0). This will only leave 2 choices left to verify!

Answer 14

A :s

Answer 15

am i wrong?

Answer 16

@kirbykirby

Answer 17

yup looks good :)

Answer 18

yay!!!

Answer 19

@kirbykirby

Answer 20

One way to do this ... for the vertex of the parabola.. if you just have an \(x^2\) term and possibly a coefficient in front of it, then the parabola will have a vertex at (0,0) (this should leave 2 possible answers).

If your coefficient is > 1, then you should expect a "squeezed" up looking parabola, but if the coefficient is < 1, then you should expected a "wide" looking parabola.

You can check a point on the parabola if it satisfies the equation. Say if x=1, then f(x) = 1/3. Does A satisfy this? no, C? possibly but 1/3 is not an exact coordinate. How about when x=3? then f(x) = 1/3* 3^2 = 1/3*9 = 3, this is satisfied on the graph C

Answer 21

so C :B

Answer 22

yes C

Answer 23

Make sure that the negative sign gets distributed across all terms in the parentheses, \((3+i)-(2-2i) =3+i-2+2i\) and then combine like-terms.

Answer 24

is it A

Answer 25

o.O am i right kirby

Answer 26

can it be ( B )

Answer 27

A :)

Answer 28

yay!! :D

Answer 29

isn't that the same question as before o.O

Answer 30

is it :o, i put A was that right?

Answer 31

yes

Answer 32

oh okay, sorry it was this one 0.0

Answer 33

Hm I'm gonna have to go though after my reply. It's very late where I am :S

But the quadratic formula for an equation \(ax^2+bx+c=0\) is:
\[ x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]

Your equation is \(-2x^2-5x+5=0\), so plug in into the quadratic formula, using \(a=-2,\,\,b=-5,\,\,c=5\)

Answer 34

Hopefully you can reduce that and obtain one of the answers posted, but I gotta go :o

Answer 35

good luck though!

Answer 36

thank you, goodnight :)

Answer 37

i think it C

Answer 38

ty