Question

Parabola simple exercise

Answer 1

simpler than finding the power series for \(\sqrt{1+x}\)?

Answer 2

I know the vertex is in (-1,0) and the focus in (1,0)

Answer 3

Totally :)

Answer 4

So I need to find the ecuation of it...and I know it is something like this (x+1)^2=4py

Answer 5

How can I obtaing p? I forgot...is it the distance from vertex to focus?

Answer 6

yes it is, ans you also know \(p=2\) since it is the distance between the focus and the vertex

Answer 7

ok, soit is (x+1)^2=8y ?

Answer 8

yup

Answer 9

we can check if you like

Answer 10

whoa some mistake here
good thing i went to check

Answer 11

And how can I find the ecuation of the directive?

Answer 12

What's wrong?

Answer 13

for one thing i wasn't paying attention
plot the points

Answer 14

(is the directive y=-3

Answer 15

ok

Answer 16

ugh :(

Answer 17

lol

Answer 18

I just did it on wolframalpha...isnt it supposed to open to the right?

Answer 19

but it is no harder, just instead of \((x+1)^2=4py\) it is \(4p(x+1)=y^2\)

Answer 20

helps to know which way it opens, right?

Answer 21

yep...you are right

Answer 22

So the directive will be x=-3...ok, got it :)

Answer 23

http://www.wolframalpha.com/input/?i=parabola+8%28x%2B1%29%3Dy^2

Answer 24

let me guess, studying for calc 2 final

Answer 25

Nope :) I already had that one...but I have a geometric analysis class

Answer 26

I have 4 different math classes :)

Answer 27

Thanks for the help