Question

the length and the breadth of a square are increased by 40% and 30% resp.the area of resulting rectangle exceeds the area of square by

Answer 1

@kropot72 ,@ganeshie8 ,@Compassionate

Answer 2

@jim_thompson5910

Answer 3

@mathslover

Answer 4

You have a square, so the length and width are equal.
Start with an easy number for the side, such as 10.
What is the area of a square with side 10?

Answer 5

A1 = L x L
A2 = 1.4L x 1.3 L

calculate either A2-A1 or, better, A2/A1

Answer 6

l^2-1.82l^2=.82l^2

Answer 7

The area of a square with side 10 is 10 * 10 = 100
Now increase the length by 40% to get 14.
Increase the width by 30% to get 13.
Now you have a rectangle with length and width 14 and 13 units, respectively.
the area of this rectangle is 14 * 13= 182

Answer 8

100-182/100*100

Answer 9

82%

Answer 10

Let's find the percent increase from 100 to 182.

\(percent~change = \dfrac{182 - 100}{100} \times 100 = 82\%\)

Answer 11

yes, 1.4 x 1.3 = 1.82 an 82% increase

Answer 12

Correct. The percent increase is 82%. The increase in area is 1.82 times.

Answer 13

@mathstudent55 is showing the best way to do one of these problems if the numbers aren't given, meaning whatever number you pick will work
a great trick to learn