Which of the following would best represent a cosine function with an amplitude of 2, a period of pi over 3, and a midline at y = 1? f(x) = cos(x − pi over 3) + 2 f(x) = 2 cos(x − pi over 3) + 1 f(x) = −2 cos 6x + 1 f(x) = −cos 6x + 2
If you require an amplitude of 2, then you'd have to eliminate the first and fourth possible answer. Note that the period of the general sine function y = a*sin (bx + c) is \[\frac{ 2\pi }{ b }\] Perhaps this alone will be enough to help you choose the correct one of the two remaining answer choices. "A midline at y = 1" implies that the whole cosine curve has been shifted upward by 1 unit.
i was leaning towards the third option...but im really not sure
It might help if you were to explain your own reasoning. why were you leaning towards the third option? Why would you set aside the other remaining option?
because there a 2 and a 3 in the question and 2x3=6 and theres a 6 in the third option... i really dont know how to solve it :(
b
thanks, can you tell me why? @gokukamehameha
i did this in k12 and i remember and it was b because i picked a on my test and it was wrong it is b
go back to mathmale's response, and look at the equation he gave you to find the period of a sine wave
the problem is i dont understand anything. the only thing i know is tht cos=adj/hyp the rest is just over my head
i think i'll go with b. but thanks to everyone for all your help :)
np
What was the correct answer?
I think it is B as well because of the structure of a typical sin functin....but this is cosine...so...
I know this is extremely old, but for any future users who need help, this could help you out: https://mathway.com/examples/Trigonometry/Graphing-Trigonometric-Functions/Amplitude-Period-and-Phase-Shift?id=342
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