Question

alg2 help?

Answer 1

\[5x/x^2 - x - 6 + 4/x^2 + 4x + 4 \]

Answer 2

@ganeshie8 @Nurali @David. @Compassionate @AccessDenied @halorazer a little help please?

Answer 3

combining like terms?
(5x/x^2)+3x+(4/x^2)-2
((5x+4)/x^2)+3x-2
I think you can do it this way or like this
5/x+3x+4/x^2-2

Answer 4

@Kkutie7 its simplifying a complex fraction

Answer 5

\[\frac{ 5x }{ x^{2} }-x-6+\frac{ 4 }{ x^{2} }+4x+4\]
\[\frac{ 5x }{ x ^{2} }+4x-2+\frac{ 4 }{ x ^{2} }\]

Answer 6

You can go a bit further and put them all over x^2 like this\[\frac{ 4x ^{3}-2x ^{2}+5x+4 }{ x ^{2} }\]

Answer 7

or just break down \[\frac{ 5x }{ x ^{2} }\] to \[\frac{ 5 }{ x }\]

Answer 8

Sorry I made a mistake \[\frac{ 5x}{ x ^{2} }+3x-2+\frac{ 4 }{ x ^{2} }\] and 4x^3 should be 3x^3

Answer 9

@Kkutie7 also when i have that where did the x-3 and x-2 come from that whole second part confuses me so much and i dont understand what they did there

Answer 10

is this the same problem? or a different one? Because the attachment is showing factoring. x^2-x-6. let's look at the top here. I do factoring like this. We need two numbers that when multiplied together equals -6 but when added equals -1. 2*3=6 3-2=1 so we know that in order to a negative 6, 3 or 2 needs to be negative. in order for there to be a - before the x 3 needs to be negative. So when we add -3+2=-1 and -3*2=-6. Put these values in here (x )(x )= (x-3)(x+2)

Answer 11

you can check this work by multiplying (x-3)(x+2)= x^2+2x-3x-6 combine like terms x^2-x-6..... here is the original equation.

Answer 12

why do we need o have two numbers that equal -1 ?

Answer 13

basically we want to look at x^2[-1x][-6] <---- these two things in the equation. we already know from the x^2 that (x )(x ). the number on the end is what determines what two numbers are multiplied. It is negative so then we know that (x- ?)(x+?). the second thing we need to look at is the number in front of the x which is a -1. this number is what determine what is negative or positive so when the two numbers are added together they equal -1 here, but different in other problems, so -3 and 2 can be plugged in (x-3)(x+2)