Question

cos theta .-. please help

Answer 1

Find the value of cos θ for the angle shown.

Answer 2

@satellite73

Answer 3

hi

Answer 4

wow that was quick and hi c: how do i go about doing this

Answer 5

not drawn to scale obviously but neither is your picture
all we need is the radius i.e. the hypotenuse

Answer 6

oh doh it is \(\sqrt{33}\) not \(\sqrt{133}\) good

Answer 7

okay so 4^2+sqrt33^2=16+33=49

Answer 8

yes so \(7\)

Answer 9

oh my satellite XD you have issues sometimes

Answer 10

lol i sure do
you good from there?

Answer 11

if not we can finish in a heartbeat
just let me know

Answer 12

so i just enter cos7 into the calc and its .99243515 .-.

Answer 13

oh no no hold the phone

Answer 14

i think you should hold the bicycle instead c:

Answer 15

we need the \(7\) so we can find the ratio of the triangle
cosine is the first coordinate divided by the hypotenuse

Answer 16

it is "adjacent over hypotenuse" for cosine, so it is
\[\cos(\theta)=\frac{4}{7}\]

Answer 17

you didnt catch my punny joke .-.

Answer 18

don't worry about the fact that you are in quadrant IV
the first coordinate is positive, it is 4
yes i did!

Answer 19

i got this bike when i traded in my first 1000 medals

Answer 20

you can trade in medals o.o

Answer 21

that was my joke
no, they are useless

Answer 22

you got the answer now? and hopefully understand how to get it?

Answer 23

aww :c you got me excited for a minute XD so i guess when people say FREE MEDALS TO BEST ANSWER on there question there really is no point

Answer 24

.-. *their question

Answer 25

with emphasis on the word "free"

Answer 26

yeah... they should still be worth something :p like how about a boarder around the picture and crap like that XD people would work for that

Answer 27

can you possibly help me with one more.-.

Answer 28

virtue is its own reward
so let me ask again, you sure you got the answer?
and yes, i will help with another

Answer 29

yay c:
how do i find a point for the terminal side of -45?

Answer 30

on the unit circle?

Answer 31

im assuming yes XD my whole lesson is on trig functions of any angle

Answer 32

@satellite73

Answer 33

there you arE
SITE CRASHED ON ME

Answer 34

the ratios of a 45-45-90 right triangle are \[\frac{\sqrt2}{2}:\frac{\sqrt2}{2}:1\]

Answer 35

if the angle is \(-45\) then you are in quadrant IV and the point is
\[(\frac{\sqrt2}{2},-\frac{\sqrt2}{2})\]

Answer 36

let me find you a nice cheat sheet with all the relevant points on the unit circle labelled

Answer 37

i have one on my other computer, hold on a second
i came to this one because the site crashed

Answer 38

that is soooo not one of my answers XD
(-3, -3)

(4, -4)

(5, 5)

(-2, 2)

Answer 39

ooh i see hold on and i will draw a picture

Answer 40

the first and second coordinate are the same in absolute value, but the second coordinate is negative because it is down, not up

Answer 41

your angle is not -45
always start on the right on the x axis

Answer 42

wait what .-.

Answer 43

the correct answer from your choices is \((4,-4)\)

let me draw another picture

Answer 44

then for \(-45\) go \(45\) degrees clockwise