Question

Can someone look at this roots problem? It's really quick.

Answer 1

\[\huge 7\sqrt{10}\times3\sqrt{5} => 7\times3\sqrt{10\times5}\]

Answer 2

So the 21st root of 50?

Answer 3

I know that what I said isn't an option.

Answer 4

ohhh.... you mean

\(\LARGE\color{black}{ \bf \sqrt[7]{10}\times \sqrt[3]{5} }\)

Answer 5

right ?

Answer 6

Yes.

Answer 7

I got suspended last time for giving out full explanation; weird, I know, but...

set the exponents equal to each other, hint.

\(\LARGE\color{black}{ \bf \sqrt[3]{50} = \sqrt[3]{\sqrt[3]{5^3} }... }\)

Answer 8

How did you get those numbers?

Answer 9

nvm, just set the roots equal to each other and multiply them together.

Answer 10

I mean the power of the roots.

Answer 11

How do I do that?

Answer 12

Can the seventh root of 10 be split into the seventh root of 2 times the seventh root of 5?

Answer 13

re-write the exponents as fractions, not as roots

find the common denominator,

Do this for now, more instructions will come (from me, unless I am offline)