Divide. 18x^3+12x-3x/6x^2 @mjoxprm360
do u know how to do this @mjoxprm360
Do you know how to factor 18x^3 + 12x – 3x?
well no is it lik but lik terms toghther or something
So, what's the greatest common factor of 18x^3 + 12x – 3x?
i think 3 am i right
haha wait wait wait here
ok wat u fina do??
do you know how to find the GCF? If not, I can walk you through it.
need a walk through?
well yes i do
Okay, so first we need to list all the prime factors of the coefficients. The coefficients are 18, 12, and 3. 3: 3 12: 2, 2, 3 18: 2, 3, 3 Now, I want you to tell me what one prime factor all of the coefficients have in common.
i know how to find the GCF
ok they all have 3 in common i just wanted to explain why
do you know how to factor the GCF out?
?
yes
ok good can you tell me what your answer for the gcf is?
yes i do know how to
3
We need to put the GCF on the left side of a set of parenthesis. Like this: 3x( ) And now we need to figure out what to put in those parenthesis. And in order to do that, we need to figure out what we can multiply by 3x to get our original expression, 18x^3 + 12x – 3x. 3x times what equals 18x^3?
ok
so i multiply
Dang, okay, don't be mad at me, but I think I read your question wrong. At first, we were supposed to combine the like-terms 12x and –3x which would equal 9x. 18x^3+9x. Are you okay with starting from scratch? It won't take as long this time since you understand the concepts.
i would never get mad at u
ok im okay with that
Yay, okay! :D We have 18x^3 + 9x. We need to find the GCF of this expression, just like last time. Do you know how to do that now?
yes
the GCF is 3
Yes, that's a factor of both of them, but not the GREATEST common factor. :D So let's list the prime factors of the coefficients, 18 and 9. 9: 3, 3 18: 2, 3, 3 They both have two 3's in common, right? We would multiply the two 3's to get the number 9. That's the first part of our GCF. Since our terms both have at least one x, we can also add the x to our GCF. So, the GCF is 9x. Does it make sense how we got that?
yess it does
Okay, we need to put it on the left side of a set of parenthesis just like last time: 9x( ) Remember our original expression, 18x^3 + 9x. 9x times what equals 18x^3?
idk :( um. is it 3x+2
2x^2
ohh ok
so wats the answer
9x(2x^2+1) Now we factored out our first term (18x^3), and now for our second term (9x). In order to get 9x from 9x, we just multiply by 1, correct? So, this is our factored form of the expression: 9x(2x2∗1) That's just the numerator, though. We need to find 9x(2x2+1)6x2 The denominator (6x^2) doesn't need to be factored. Now that we have both the numerator and the denominator factored, we can begin to divide out terms. Do you know how to do that?
You divide like terms
um........ noo but is it jus dividing the like terms
9x(2x2+1)6x2 Do you know what the greatest common factor of 6 and 9 is? In other words, what's the greatest number than can divide into both of them?
its 3 again
Yes! So 9÷3 is 3, and 6÷3 is 2. We can divide those out so we get: 3x(2x2+1)2x2 Do you see that both the numerator and the denominator have at least 1 "x" in them? (The numerator has 1 x, and the denominator has 2 x's.)
That is, at least one x outside of the parenthesis
ok yea i see that
Okay, good. So we can cancel out 1 "x" from the numerator and the denominator. 3(2x2+1)2x Since we can't divide anything else out, that would be your answer. Does it make sense how we got that?
yes it does
great!
XD awesomee
so wats the answer
\[3(2x ^2+1 \frac{ 2 }{ x }\]
thanx ndf u sure
wait is that the answer
3(2x2+1)2x
ok thanx
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