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Mathematics 12 Online
OpenStudy (anonymous):

Of 6 seniors and 7 juniors, 5 will be selected for a scholarship. What is the probability that exactly 3 of 5 students selected will be seniors?

OpenStudy (anonymous):

@satellite73 @ganeshie8 @AccessDenied

OpenStudy (anonymous):

@mathmale

OpenStudy (kropot72):

\[P(3\ out\ of\ 5\ be\ seniors)=\frac{6C3\times7C2}{13C5}=you\ can\ calculate\]

OpenStudy (anonymous):

oh this makes sense! because if 3 are seniors 2 must be juniors! thank you so much!

OpenStudy (anonymous):

what equation is this by the way?

OpenStudy (kropot72):

You're welcome :)

OpenStudy (kropot72):

The equation is for the hypergeometric distribution.

OpenStudy (kropot72):

The hypergeometric distribution is generated when a sample of size n is taken (without replacement) from a population containing a items of one particular type, and b of another type. The probability that the sample contains exactly x of the particular type is given by: \[P(x)=\frac{{a \choose x} {b \choose n-x}}{{a+b \choose n}}\]

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