Of 6 seniors and 7 juniors, 5 will be selected for a scholarship. What is the probability that exactly 3 of 5 students selected will be seniors?
@satellite73 @ganeshie8 @AccessDenied
@mathmale
\[P(3\ out\ of\ 5\ be\ seniors)=\frac{6C3\times7C2}{13C5}=you\ can\ calculate\]
oh this makes sense! because if 3 are seniors 2 must be juniors! thank you so much!
what equation is this by the way?
You're welcome :)
The equation is for the hypergeometric distribution.
The hypergeometric distribution is generated when a sample of size n is taken (without replacement) from a population containing a items of one particular type, and b of another type. The probability that the sample contains exactly x of the particular type is given by: \[P(x)=\frac{{a \choose x} {b \choose n-x}}{{a+b \choose n}}\]
Join our real-time social learning platform and learn together with your friends!