Question

@mathslover

Answer 1

Choices
csc <C = 3/2
sec <C = 5/6
csc <B = 3/2
sec <B = 6/5

Answer 2

Given the triangle below, which of the following is a correct statement?

Answer 3

What did you get?

Answer 4

I got D

Answer 5

\[4^2+5^2=6^2~~~~~is~~NOT~~true~~!!\]

Answer 6

Nope, that is not correct.

Yeah Solomon, 90 degree should not be there.

Answer 7

Remember this :

\(\sin \theta = \cfrac{1}{\csc \theta}\) or \(\csc \theta = \cfrac{1}{\sin \theta}\)

\(\cos \theta = \cfrac{1}{\sec \theta}\) or \(\sec \theta = \cfrac{1}{\cos \theta}\)

Answer 8

So, \(\csc C = \cfrac{1}{\sin C}\)

And since, \(\sin C = \cfrac{opposite}{hypotenuse}\)

So, \(\csc C = \cfrac{hypotenuse}{opposite}\)

Answer 9

Hypotenuse = 6 and opposite = 4

so, you get \(\csc C = \cfrac{6}{4} = \cfrac{3}{2}\)

Answer 10

So, our answer should be A)

Answer 11

One more tip, I think it would be good to say this.

A secant or cosecant can never be equal to one or less, it is always more than 1.

Answer 12

That;'s why you can eliminate choice B without even looking at anything.

Answer 13

thanks

Answer 14

thank mathsolver :)

Answer 15

thank you, Mathsolver !

Answer 16

Solomon has provided a nice tip but to avoid confusion, I will edit it a bit :

Cosec and Sec functions can never be between 0 (including) and 1(excluding) . As cosec and sec functions can be equal to 1 :

sec 0 = 1
cosec 90 = 1

They can be negative .

Answer 17

yes, mathsolver.. I meant the absolute value ... tnx again everyone \(\LARGE\color{black}{ \bf : }\)\(\LARGE\color{red}{ \bf ) }\)