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Show that \(\sin^{-1}(x) + \cos^{-1}(x) = \dfrac{\pi}{2}\) for \(|x| \leq 1\)
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What identifies would be great for me to use? I just need me some leads...
derivative? it would get me to 0 = 0. ok so I know arcsin(x) + arccos(x) should be equal to constant, but why pi/2 ?
@Loser66
I don't know, but why not pi/2? it's a number, still
we can't just make up what it equal to, that's not really math lol...
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|dw:1399956642198:dw|
x+y=pi/2 y=pi/2-x Put sin x=k sin y=l sin^-1 k+sin^-1 l=x+pi/2-x=pi/2
Is that explanation convincing? :)
hmm yeah. good enough lol. thanks! I was just curious.
yw :)
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