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How many photons are produced in a laser pulse of 0.649 J at 535 nm?
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use this relaTION \[E=H \nu \] where E is the energy of a single photon, and ν is the frequency of a single photon again if a photon traveling at the speed of light c and a frequency ν will have a wavelength λ given by \[\lambda=c/\nu \] \[E=hc/λ\] \[E=(6.626×10^{-34})(2.998×10^{8})/(535×10^{-9})=3.71×10^{-19} J\] To find out how many photons are in a laser pulse of 0.649 Joules, we simply divide the pulse energy by the photon energy so number pf photons \[N=\frac{ 0.649 }{ 3.71*10^{-19} }=1.7*10^{18}\]
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