Mathematics
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OpenStudy (anonymous):
How would you solve this? Attached inside! :) thanks! :D
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OpenStudy (anonymous):
problem!
OpenStudy (anonymous):
OpenStudy (anonymous):
The integral looks like this: |dw:1399958609432:dw| after we substitue in the values we know
hero (hero):
Because they stated that \(f(t) = F'(t)\) So
\(\int f(t) dt = \int F'(t)dt\)
hero (hero):
\(F(t) = t^2\)
So @iheartfood, \(F'(t) = ?\)
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OpenStudy (anonymous):
ermm is it using one of the a or b values? :/
OpenStudy (anonymous):
like would t mean F(b) - F(a) ?
hero (hero):
We'll get to that in a minute. For this, you need to focus on one step at a time. Just calculate \(F'(t)\) for the moment.
OpenStudy (anonymous):
okay:)
umm it equals f(t) ?
OpenStudy (anonymous):
not quite sure how to find the exact value of f(t) :(
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hero (hero):
Actually \(F(t) = t^2\)
OpenStudy (anonymous):
ohhhhh okay
hero (hero):
So we can easily find \(F'(t)\)
OpenStudy (anonymous):
2t?
hero (hero):
Correct...
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OpenStudy (anonymous):
yay! :)
hero (hero):
So now, \(F'(t) = 2t\) and a = 1 b = 4 so
\[\int_{1}^{4} 2t dt\]
hero (hero):
You should be able to compute that relatively easily.
OpenStudy (anonymous):
okay:)
OpenStudy (anonymous):
2(4) + 2(1) ? :/ not really sure of this part :/
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OpenStudy (anonymous):
The formula is F(b) - F(a)
It's correct but replace the plus sign with a negative one
OpenStudy (anonymous):
ohh okay so 8 - 2 = 6?
OpenStudy (anonymous):
Yup
OpenStudy (anonymous):
ohh so it'll look like this? |dw:1399959312498:dw|