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Mathematics 14 Online
OpenStudy (anonymous):

How would you solve this? Attached inside! :) thanks! :D

OpenStudy (anonymous):

problem!

OpenStudy (anonymous):

OpenStudy (anonymous):

The integral looks like this: |dw:1399958609432:dw| after we substitue in the values we know

hero (hero):

Because they stated that \(f(t) = F'(t)\) So \(\int f(t) dt = \int F'(t)dt\)

hero (hero):

\(F(t) = t^2\) So @iheartfood, \(F'(t) = ?\)

OpenStudy (anonymous):

ermm is it using one of the a or b values? :/

OpenStudy (anonymous):

like would t mean F(b) - F(a) ?

hero (hero):

We'll get to that in a minute. For this, you need to focus on one step at a time. Just calculate \(F'(t)\) for the moment.

OpenStudy (anonymous):

okay:) umm it equals f(t) ?

OpenStudy (anonymous):

not quite sure how to find the exact value of f(t) :(

hero (hero):

Actually \(F(t) = t^2\)

OpenStudy (anonymous):

ohhhhh okay

hero (hero):

So we can easily find \(F'(t)\)

OpenStudy (anonymous):

2t?

hero (hero):

Correct...

OpenStudy (anonymous):

yay! :)

hero (hero):

So now, \(F'(t) = 2t\) and a = 1 b = 4 so \[\int_{1}^{4} 2t dt\]

hero (hero):

You should be able to compute that relatively easily.

OpenStudy (anonymous):

okay:)

OpenStudy (anonymous):

2(4) + 2(1) ? :/ not really sure of this part :/

OpenStudy (anonymous):

The formula is F(b) - F(a) It's correct but replace the plus sign with a negative one

OpenStudy (anonymous):

ohh okay so 8 - 2 = 6?

OpenStudy (anonymous):

Yup

OpenStudy (anonymous):

ohh so it'll look like this? |dw:1399959312498:dw|

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