Question

f''x = 2+cosx f(0)=-1 and f(pi/2)=0
Find f(x).

Answer 1

find f(x)

Answer 2

integrate twice

f'(x) = 2x +sin x + C

f(x) = x^2 -cos x + Cx + K

use the two initial values to find constants C,K

Answer 3

but both given values are to plug in the original function...how can we solve for Cx?

Answer 4

@dumbcow do u have any clue how to go further on?

Answer 5

first put x=0 in the equation f(x) = x^2 -cos x + Cx + K
u'll get K

Answer 6

but how do we know which one we have to use first?

Answer 7

if u put x=0 then c will be eliminated and u cal calculate K and then C
but if u put x=pi/2 then both K and C will be there

Answer 8

f(0)=-1
-1+k=-1
k=0
now u have f(x)= x^2 -cos x + Cx now put x=pi/2
f(pi/2)=0
0=pi^2/4+(C*pi)/2
c=-(pi/2)

Answer 9

OMG i get it now!! thank uu

Answer 10

np:)