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lnx - ln5 =4 how would I solve show process please
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Use \[\log a -\log b=\log \dfrac{a}{b}\]
umm how would i go about this?
Just compare the terms with the equation I gave above lnx - ln5 =?
ln -x/5?
im kinda confused what to do with the 4
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log x/5=4 This means e^4=x/5 You can solve for x now!
ohh I understand now so x=5e^4
AravindG, I thought it would become\[\ln(\frac{x}{5})=4\](not log, but ln, with base e)
Yes I was referring to natural log. You can see that I took e in the end though.So no worries :)
Yes @itsJonLe :)
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Yeah :)
okay thank you very much!! :DD
yw :)
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