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A charged oil drop with a mass of \(2 \times 10^{-4} \) kg is held suspended by a downward by an Electric field of 300 N/C . Find the charge on the drop.
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\(\color{blue}{\text{Originally Posted by}}\) @mathslover A charged oil drop with a mass of \(2 \times 10^{-4} \) kg is held suspended by a downward by an Electric field of 300 N/C . Find the charge on the drop. \(\color{blue}{\text{End of Quote}}\)
@ganeshie8
sorry cant help you there
No problem :)
Weight is balanced by the electrostatic force. mg = |q|E => |q| = mg/E Now, if field is downward, since electrostatic force must be up, the q is negative. So final answer is : q = -mg/E
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Got it Sir. Thanks!
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