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Mathematics 13 Online
OpenStudy (anonymous):

Ratio help please!

OpenStudy (anonymous):

OpenStudy (tkhunny):

How much does the smaller bottle hold? NAME it. Seriously, just give it a name. You'll be about half way done.

OpenStudy (anonymous):

small can be y, large can be x

OpenStudy (tkhunny):

Can you translate in terms of x and y? "Smaller contains 6 more than half the large."

OpenStudy (anonymous):

y=(x/2)+6

OpenStudy (tkhunny):

I think you have it. Now, set up the proportion.

OpenStudy (anonymous):

Thats what I'm having trouble with.

OpenStudy (djjo):

Two bottles have capacities in the ratio 4 to 7. The smaller bottle holds 6 ounces more than half of the larger bottle. How many ounces will the smaller bottle hold? let x be the smaller bottle and y is the larger x/y = 4/7 x = ½y + 6 substitute the value of x in the first equation x/y = 4/7 (½y + 6)/y = 4/7 7(½y + 6) = 4y (7/2)y + 42 = 4y multiply both sides by 2 7y + 84 = 8y 84 = 8y - 7y 84 = y x = ½y + 6 x = (½)(84) + 6 x = 42 + 6 x = 48 So how many ounces are there?

OpenStudy (tkhunny):

Dear @DJJo , please don't change variables in the middle of the problem. We already defined y = smaller and x = larger. Your opposite definition is strenuous.

OpenStudy (djjo):

ok, i'll try to make it less confusing next time

OpenStudy (tkhunny):

You may also wish to consider letting the student show some work rather than you doing it all. You can't be there on an exam.

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