Question

A child is given a push on a swing.Each time she swings back a little less, according to the equation d=2(0.85)^n , where d is the horizontal distance, in metre, from her position after n complete swings. After how many swings will the distance from rest be less than 15cm.

Answer 1

mch

Answer 2

what?

Answer 3

Well the equation we are given...is in meters....

\[\large d = 2(0.85)^n\]

However what they want to know..is how long it will take to be less than 15 CM....so lets convert 15 centimeters to meters....we do that by dividing by 100

\[\large 15cm \times \frac{.01m}{1 cm}= .15m\]

Now we just make our equation

\[\large d = 2(0.85)^n \le .15\]

and solve for 'n'

Answer 4

Do you know how to solve for 'n' @harz360 ?

Answer 5

trial and error?

Answer 6

anyone please help me