Question

HELP WILL REWARD!

What is the period of the function?
y = 4 cos pi x

A. 1
B. 2
C. pi
D. 2pi

Answer 1

let me see

Answer 2

okay

Answer 3

afk for a bit k

Answer 4

back

Answer 5

okay i'll be doing it

Answer 6

okay

Answer 7

hmm its not coming to be clearly All i'am getting is this cos(pi.x) = 1 when x = 0, as cos(pi.0) = cos(0) = 1

Answer 8

y=4sin(pi x) 4 2 2pi 2/pi 3

Answer 9

Recall that the period for y = a*cos(bx + c) + d is given by 2π/|b|.

Since y = cos(πx) = 1*cos(πx + 0) + 0, we see that b = π. Therefore, the period is:
2π/|b| = 2π/|π| = 2π/(π) = 2.

I hope this helps, if not go to the link if you didn't recall anything ok.

Answer 10

https://www.google.com/search?q=What+is+the+period+of+the+function%3F+y+%3D+4+cos+pi+x&oq=What+is+the+period+of+the+function%3F+y+%3D+4+cos+pi+x&aqs=chrome..69i57.997j0j9&sourceid=chrome&es_sm=122&ie=UTF-8#q=+What+is+the+period+of+the+function%3F++y+%3D+4+cos+pi+x+