Can someone show me how to do this quickly? Use the law of sines to find the missing angle of the triangle. Find m ∠C to the nearest tenth/
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A. 11.1 degrees Or B. 58.8 degrees.
@whpalmer4 @kropot72
@johnweldon1993
Ahh the law of sines lol \[\large \frac{sinA}{a} = \frac{sinB}{b} = \frac{sinC}{c}\]
So this means if we have an angle of A...and a side of a......along with at least 1 other angle...or 1 other side...we can solve for the missing (angle or side) that we need... So here We have angle A...and the corresponding side A We also have side c...so we can solve for angle C
\[\large \frac{sin(24^\circ)}{77} = \frac{sin(C)}{162}\]
Now we just need to isolate \(\large sin(C)\) which would look like...?
Sin24/77 x sin c/162
I don't understand the isolating part.
Do I just solve for C ?
That's alright :) so yes we have \[\large \frac{sin(24^\circ)}{77} = \frac{sin(C)}{162}\] If we cross multiply here (can only do this with ratios... this fraction = that fraction) we would have \[\large 162sin(24^\circ) = 77sin(C)\] does that make sense? Just multiply |dw:1400024447563:dw|
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