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Mathematics 16 Online
OpenStudy (anonymous):

Related Rates Problem

OpenStudy (anonymous):

Ill post my work next

OpenStudy (anonymous):

Here

OpenStudy (sleepyhead314):

I'm not all that good at related rates... and I have absolutely no idea how to do your problem... but have you tried getting a r to h ratio so you can replace an r with an h or an h with an r into v = 1/3 pi r^2 h to make the problem easier?

OpenStudy (anonymous):

yeah ive solved for everything except r' aka: (dr/dt)

OpenStudy (sleepyhead314):

yeah... hit the same wall before... http://openstudy.com/users/jeffsours#/updates/535e8c33e4b0b5bc4da6fb13 couldn't find dr/dt so you have to get ratio of radius to height to get just two variables in the v = 1/3 pi r^2 h equation

OpenStudy (anonymous):

yeah i got 4 of the 6 variables, if i could figure out how to pull dr/dt i could solve

OpenStudy (sleepyhead314):

pulling dr/dt out of there means taking out r from the original equation... like IF the ratio was r = 3h then you can get V = 1/3 pi (3h)^2 h simplify, derive and won't have to deal with the dr/dt

OpenStudy (sleepyhead314):

erm... also, for 2.75/9 = x/5 -> x = 13.75/9 right? :/

OpenStudy (sleepyhead314):

2.75/9 = 11/36 r in terms of h -> 36h/11 plug in for r... V=1/3 pi r^2 h --> V = 1/3 pi (36h/11)^2 h --> V = (432/121) pi h^3 -> dV/dt = (1296/121) pi h^2 (dh/dt) = (1296/121) pi (5)^2 (20) = (648000/121)pi -> (648000/121)pi + 7300 is what I got :/ idk if it right tho...

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