Logarithm help?
logx to the base 2 = a means the number is x=2^a log a + log b = log(ab) adding logs is the same as log of their product take antilog of all the values in your equation (2^15)(2^14)/(2^105) = x x = 2^(29-105) = 2^(-76) = (1/2)^76
Can you explain it in even more detail because I'm completely lost?
@tkhunny @mathmale
we are going to solve the problem by converting log x to x, this is done by taking the anti-log of each term for base 2 logarithms, the anti log of (log z) is 2^z.
Oh okay I think I get it now my brain was registering getting rid of the log all together. Thank you!
you could also do this \[\log(15)+\log(14)-\log(105)=\log(\frac{15\times 14}{105})\]
since \(\frac{15\times 14}{105}=2\) you have \[\log(2)=\log(x)\] making \(x=2\) the base is not important in this question, would work the same way for any base
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