write parabola in standard form: x^2-2x+8y+17=0

Question

anonymous · Answer

So far i have attempted this problem but feel my work looks strange, I ended up with this as my answer:
8(y-(137/8)^2)=(x-1)^2

anonymous · Answer

standard form like 
$$(x-h)^2=4py$$ that kind of standard form?

anonymous · Answer

yes @satellite73 that is correct!

anonymous · Answer

$$ x^2-2x+8y+17=0$$ start with 
$$x^2-2x=-8y-17$$ then complete the square on the left
i have no idea how you got your answer!

anonymous · Answer

it would be (x-1)^2

anonymous · Answer

for the left side!

anonymous · Answer

yes
and how about for the right?

anonymous · Answer

thats where i think i got stuck i wasnt sure what to do :|

anonymous · Answer

add 1!

anonymous · Answer

$$(x-1)^2=x^2-2x+1$$ you added 1 to the left, you have to add 1 to the right

anonymous · Answer

thats right!

anonymous · Answer

so then,

anonymous · Answer

i would have -8y -16 .... -8(y+2)

anonymous · Answer

guess so yes

anonymous · Answer

wow not nearly as hard as all those other questions you usually ask!

anonymous · Answer

haha your always here to help me! this section is review and i haven't done this in years so its faded :|

anonymous · Answer

yeah that algebra gets you every time!

anonymous · Answer

sadly yes :| lol