Question

write parabola in standard form: x^2-2x+8y+17=0

Answer 1

So far i have attempted this problem but feel my work looks strange, I ended up with this as my answer:
8(y-(137/8)^2)=(x-1)^2

Answer 2

standard form like
\[(x-h)^2=4py\] that kind of standard form?

Answer 3

yes @satellite73 that is correct!

Answer 4

\[ x^2-2x+8y+17=0\] start with
\[x^2-2x=-8y-17\] then complete the square on the left
i have no idea how you got your answer!

Answer 5

it would be (x-1)^2

Answer 6

for the left side!

Answer 7

yes
and how about for the right?

Answer 8

thats where i think i got stuck i wasnt sure what to do :|

Answer 9

add 1!

Answer 10

\[(x-1)^2=x^2-2x+1\] you added 1 to the left, you have to add 1 to the right

Answer 11

thats right!

Answer 12

so then,

Answer 13

i would have -8y -16 .... -8(y+2)

Answer 14

guess so yes

Answer 15

wow not nearly as hard as all those other questions you usually ask!

Answer 16

haha your always here to help me! this section is review and i haven't done this in years so its faded :|

Answer 17

yeah that algebra gets you every time!

Answer 18

sadly yes :| lol