find 3 consecutive odd integers whose sum is 111
i guess 31,33,35 but that is not right try 3 larger ones
36,37,38
better guess, except 38 is even
oops suppose to be odd nvm
help plz
keep guessing try numbers larger than 31,33,35 eventually you will get it
probably in only one or two more tries
An odd integer can be written in the form: \[2k + 1 \]\[\forall_k \in Z\] to find 3 consequtive integers it can be written as \[(2k+1) + (2(k+1) + 1) + (2(k+2) + 1)\] and solve for k to get your answer
Which sentence contains an incorrectly punctuated appositive or appositive phrase? A. The big winner at yesterday's game was Dan's team, the former underdogs. B. You must be home by eight o'clock your curfew time. C. The movie Shrek is one of my favorites. help
forgot to metion that equation is equal to 111 to solve for k and then substitutie it back in to get your 3 consequtive integers
You can follow satellite's method and keep guessing until you find the answer. If you need to use an equation, then read below. Choose x to represent the smallest of the 3 numbers. Then the next larger number is x + 2. The largest of the 3 numbers is x + 4. Their sum is 111, so you have x + (x + 2) + (x + 4) = 111 Now drop the parentheses on the left side and add like terms. Solve the equation for x. That gives you the smallest of the three numbers. Add 2 to the value of x to find the middle number, and add 2 to the middle number to find the largest number.
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