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Mathematics 11 Online
OpenStudy (anonymous):

Hi please help with solving the equation to two unknowns here for some reason I'm not getting it. I know the answer I just need the working to understand it please

OpenStudy (anonymous):

OpenStudy (anonymous):

I have \[\sum_{}^{} F _{x}=0; 0 = WC \cos 30^{o} - 1.375 Cos \theta \]

OpenStudy (anonymous):

\[\sum_{}^{}F _{y}=0; 0=WC \sin30^{o} + 1.375 \sin \theta - 1.5\]

OpenStudy (anonymous):

Im stuck at solving for the angle and the WC, my answer is always wrong :(

OpenStudy (anonymous):

can u specify which problem is it? 3-12 or 3-13?

OpenStudy (anonymous):

sorry 3.13

OpenStudy (anonymous):

its been a while since i did this so my memory is vague, i will need ur help if ok? what's WC?

OpenStudy (anonymous):

weight at C :) ty

OpenStudy (anonymous):

let me google a bit

OpenStudy (anonymous):

u need to have to sum of forces, one over the X axis and the other over the Y axis, let me think more

OpenStudy (anonymous):

two sums not 'to'

OpenStudy (anonymous):

@miszery can we say over the X-axis the following? 1.375 cos theta = Wc cos 30

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

so that's ur 2nd equation then Wc = (1.375/cos30) . cosTheta and can u substitue Wc above in ur first equation to find Theta?

OpenStudy (anonymous):

i try to but I get sin theta and cos theta and Im confused how to solve equation with two different trig functions :(

OpenStudy (anonymous):

isn't sin = 1/cos or am I wrong?

OpenStudy (anonymous):

I forgot the relation but there was one between the 2 I think one is sin2 + cos2 = 1 ??

OpenStudy (anonymous):

i dont know sorry I can't remember the trig identities :S

OpenStudy (anonymous):

you may be right i'll have to chech that out

OpenStudy (anonymous):

@ganeshie8 hi, do u know much about forces in physics ? kind of stuck on this :(

ganeshie8 (ganeshie8):

horizontal components : \(1.375*\cos(\theta) - C*\cos(30) =0\) looks good to me

OpenStudy (anonymous):

solving the 2 equations over X and Y axis to find Theta and Wc is the hard bit

ganeshie8 (ganeshie8):

vertical components : \(-1.5+ 1.375*\sin(\theta) + C*\sin(30) = 0 \)

ganeshie8 (ganeshie8):

do u remember the triangle method for equilibrium ?

OpenStudy (anonymous):

that's correct, both @miszery and I got that but can progress any further

OpenStudy (anonymous):

let me look it up

ganeshie8 (ganeshie8):

me too...

OpenStudy (anonymous):

equation I Wc + 2.75 sinTheta = 3

OpenStudy (anonymous):

1.588 cos T + 2.75 sin T = 3 , where T = Theta what is Theta (T) ?

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