Question

limits x approaches 5 ((sqrt x + sqrt 5)/(x-5))

Answer 1

\[\lim_{x \rightarrow 5} \frac{ (\sqrt{x}-\sqrt{5) } }{ x-5 }\]

Answer 2

Can I help you Ma'am ?

Answer 3

is the answer to this \[\frac{ 1 }{\sqrt{10}}\]

Answer 4

Show your working

Answer 5

multiply both top and bottom by reciprocal (Sqrt x + Sqrt 5) then your left with x-5 over (x-5)(Sqrt x+Sqrt 5). the x-5 cancel and then its 1/(Sqrt x+sqrt5). then you take the lim and its\[\frac{ 1 }{ \sqrt{5}+\sqrt{5} } = \frac{ 1 }{ \sqrt{10} }\] right?

Answer 6

Yes it seems to me correct, great work. Keep it up!

Answer 7

Thank you :)

Answer 8

My Pleasure. Ask help when ever you like to, I am there to help you

Answer 9

Ok what about \[\lim_{x \rightarrow 0}\frac{ sinx }{ x ^{2}+2x}\] do i just do the same thing by multiplying by reciprocal?

Answer 10

it's called commponendo and divinendo.

Answer 11

what is?

Answer 12

multiplying by reciprocal

Answer 13

ok.. how would i start this?

Answer 14

Ok show your first step

Answer 15

i would factor the bottom\[\frac{ \sin x }{ x(x+2) }\] and \[\frac{ \sin x }{ x }= 1\] so then the answer is \[\frac{ 1 }{ 2 }\]

Answer 16

your answer seems correct to me.

Answer 17

Thank you soo much

Answer 18

My Pleasure again