Question

can help me solve integral 1/surt3x dx

Answer 1

\[\int\limits \frac{ 1 }{ \sqrt{3x} }dx\]

Answer 2

yeap

Answer 3

ok , continue

Answer 4

mimi , u r incorrect

Answer 5

\[\frac{ 1 }{ \sqrt{3} } \int\limits \frac{ 1 }{ \sqrt{x} }dx => \frac{ 1 }{ \sqrt{3} }\times2\sqrt{x}+C\]

Answer 6

the ans is 2 surt x/3 plus c

Answer 7

\[\frac{ 2\sqrt{x} }{ \sqrt{3} }+C\]

Answer 8

ya batman correct

Answer 9

batman teach me plz

Answer 10

Factored out the constant \[\frac{ 1 }{ \sqrt{3} }\]

Answer 11

ok wait

Answer 12

is there anyway I can do without splitting the fracion ?

Answer 13

And the derivative of \[\frac{ 1 }{ \sqrt{x} } \ is\ 2\sqrt{x}\]

Answer 14

u ahven answer my question

Answer 15

*haven

Answer 16

It'll make your life harder

Answer 17

You can try it out, but I have no interest.

Answer 18

lol not helping ...

Answer 19

I don't know what you want?

Answer 20

u try solving it without splitting

Answer 21

I didn't split anything, I just factored out the constant.

Answer 22

try \(x = 3 \sin^2 \theta\)

Answer 23

try do without factorise

Answer 24

^if you want to make the simple problem challenging :P

Answer 25

I want see two method ( my exam will ask )

Answer 26

Why would I want to make it harder on myself.

Answer 27

Ohk, there are plenty of ways to do this actually... let me think of next best method

Answer 28

I guess you can try what rational mentioned, but I doubt it'll get you anywhere.

Answer 29

I got wrong for this in exam and Im pissed off , I did without factorizing , I just move the surt 3x to the top and start integrating and put differentiate inside at the bottom ......