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Mathematics 23 Online
OpenStudy (anonymous):

Which of the following is a solution to square root of x minus 2 end root plus 5 equals 9 ? A. x = -2 B. x = -6 C. x = 18 D. x = 16

OpenStudy (anonymous):

OpenStudy (anonymous):

give me a sec !!

OpenStudy (anonymous):

\[\sqrt{x+2}+2=5 \] \[\sqrt{x+2}=1-5\] \[(\sqrt{x+2})^{2}=-4^{2}\] x+2=16 find x

OpenStudy (anonymous):

get it ??

OpenStudy (anonymous):

just wondering how'd you get square root of x+2 end root +2 = 5 from the picture I provided above?

OpenStudy (anonymous):

@Gegomohamed

OpenStudy (anonymous):

from Equation button :D !

OpenStudy (anonymous):

:D

OpenStudy (anonymous):

\[\sqrt{x-2}+5=1\]

OpenStudy (anonymous):

@Gegomohamed

OpenStudy (anonymous):

right :D

OpenStudy (anonymous):

thats the equation so how did you get\[\sqrt{x+2}+2=5\] from that?

OpenStudy (anonymous):

oh sorry :(( i'm confused :D i'll resolve it

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

\[\sqrt{x-2}+5=1\] \[\sqrt{x-2}=1-5\] \[(\sqrt{x-2})^{2}=(-4)^{2}\] x-2=16 x=16-2 x=14

OpenStudy (anonymous):

sorry for the first wrong answer :(( but 14 isn't at a choices !! are you sure that choices are correct ??

OpenStudy (anonymous):

A. x = -2 B. x = -6 C. x = 18 D. x = 16 these are the answers provided @Gegomohamed

OpenStudy (anonymous):

MMmmmm I'm not sure try it by yourself and tell me :((

OpenStudy (anonymous):

\[\sqrt{x-2}+5=1\] subtract 5 from both sides \[\sqrt{x-2}=-4\] Then square both sides \[(\sqrt{x-2})^{2} = (-4)^{2}\] get rid of the square root and square -4 \[x-2=16\] add two to both sides and you get \[x = 18 \] The answer is C

OpenStudy (anonymous):

@Gegomohamed

OpenStudy (anonymous):

oooooooooooooh I put 16-2 not 26+2 ^_^ OMG now I'm very very shy

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