Which of the following is a solution to square root of x minus 2 end root plus 5 equals 9 ? A. x = -2 B. x = -6 C. x = 18 D. x = 16
give me a sec !!
\[\sqrt{x+2}+2=5 \] \[\sqrt{x+2}=1-5\] \[(\sqrt{x+2})^{2}=-4^{2}\] x+2=16 find x
get it ??
just wondering how'd you get square root of x+2 end root +2 = 5 from the picture I provided above?
@Gegomohamed
from Equation button :D !
:D
\[\sqrt{x-2}+5=1\]
@Gegomohamed
right :D
thats the equation so how did you get\[\sqrt{x+2}+2=5\] from that?
oh sorry :(( i'm confused :D i'll resolve it
thanks
\[\sqrt{x-2}+5=1\] \[\sqrt{x-2}=1-5\] \[(\sqrt{x-2})^{2}=(-4)^{2}\] x-2=16 x=16-2 x=14
sorry for the first wrong answer :(( but 14 isn't at a choices !! are you sure that choices are correct ??
A. x = -2 B. x = -6 C. x = 18 D. x = 16 these are the answers provided @Gegomohamed
MMmmmm I'm not sure try it by yourself and tell me :((
\[\sqrt{x-2}+5=1\] subtract 5 from both sides \[\sqrt{x-2}=-4\] Then square both sides \[(\sqrt{x-2})^{2} = (-4)^{2}\] get rid of the square root and square -4 \[x-2=16\] add two to both sides and you get \[x = 18 \] The answer is C
@Gegomohamed
oooooooooooooh I put 16-2 not 26+2 ^_^ OMG now I'm very very shy
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