Question

39) The center of mass of a cone of base radius R and height h is located at:

Answer 1

at height 3h/4 from base.
derivation:\[\int\limits_{0}^{h}(\rho(xcot \theta)^2 \pi*x*dx)/M\]
where h=height of cone and M = mass of cone
M=volume*density
volume=\[1/3*\pi*R^2*h\]
density= ρ
Note:if h is height,radius will be hcotθ