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Mathematics 14 Online
OpenStudy (anonymous):

Sigma Notation Word Problem.

OpenStudy (anonymous):

@Vallarylynn16

OpenStudy (solomonzelman):

In which answer choice, is the "slope " 2, and when i=1 then the first jump is 6 ?

OpenStudy (solomonzelman):

By slope I mean the coefficient of i

OpenStudy (solomonzelman):

Why slope (rate of growth) 2? because she jumps +2 more each next time.

OpenStudy (anonymous):

I am not sure because I still don't fully understand these. Would it be possible for you to give me the answer with an explanation for next time?

OpenStudy (anonymous):

@SolomonZelman @Yttrium

OpenStudy (solomonzelman):

I am not getting why in each choice, below the sigma, does it say i=2, when it should be i=1 ?

OpenStudy (anonymous):

No, it's supposed to be i=2 in this equation, apparently.

OpenStudy (anonymous):

@SolomonZelman

OpenStudy (anonymous):

Yttrium, do you have an idea on this?

OpenStudy (yttrium):

First of all, the former question denotes to give a derived equation from i = 4 to i = 12

OpenStudy (yttrium):

I just didn't get the first choices.

OpenStudy (yttrium):

In i = 1. We must have a value of 6. if i = 2, 8. if i = 3, 10 and so on. So we can see that it is a geometric progression having r = 2. So from that we can derive an equation which is 2i. But since our first term started at 6. We need to add 4. Hence, the derived equation is \[\sum (2i + 4)\]

OpenStudy (anonymous):

@Yttrium What about the top/bottom of the sigma and the jumps?

OpenStudy (yttrium):

depends upon the question. the question tells that derive an equation from 4tn to 12th, so it should be (4,12) and for the next q is (2,10). Just evaluate the summation to arrive at an answer.

OpenStudy (anonymous):

I don't understand this stuff though, seriously. I need help on this question, it's the first of this type that I've done ;_;

OpenStudy (yttrium):

Do you know integrals?

OpenStudy (anonymous):

If I did, I forget it.

OpenStudy (anonymous):

NEVERMIND! Found my way to 144 Jumps and it's correct. :D

OpenStudy (yttrium):

he question tells that derive an equation from 4tn to 12th, so it should be (4,12) the equation will look like this \[\sum_{4}^{12} (2i+4)\]

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