Question

Need help.

Answer 1

ok

Answer 2

cant help did that already and cant remember clearly, ill give you the close but wrong answer sorry

Answer 3

alright thank u

Answer 4

Okay, can you tell me what does it mean to say \(\Large\color{purple}{ \bf \frac{f(x)}{g(x)} }\) ?

Answer 5

When you have for instance

\(\Large\color{green}{ \bf d(x)=2x^{2}-2 }\) and \(\Large\color{red}{ \bf v(x)=x+1 }\)

to say \(\Large\color{blue}{ \bf \frac{d(x)}{v(x)} }\) simply means

\(\Large\color{blue}{ \bf \frac{ \color{green} { 2x^{2}-2 } }{ \color{red} { x+1 } } }\)

Answer 6

So when you say f/g what does that mean in YOUR case ?

Answer 7

x/x

Answer 8

Recalling that \(\Large\color{blue}{ \bf f(x)= 3x-6 }\) and \(\Large\color{blue}{ \bf g(x)=x-2 }\)

What is \(\Large\color{blue}{ \bf \frac{f}{g} }\) ?

Answer 9

3x-6 / x-2

Answer 10

Yes.

\(\Large\color{blue}{ \bf \frac{~3x-6~}{~x-2~} }\) can you factor the top, and then simplify the fraction ?

Answer 11

D

Answer 12

am i wrong? :( @SolomonZelman

Answer 13

First tell me what you get after factoring the top and simplifying the \(\Large\color{blue}{ \bf \frac{~3x-6~}{~x-2~} }\) .

Answer 14

ok so 6/2 is 3 3x/x is 3 so it will be C

Answer 15

@SolomonZelman

Answer 16

Yes, the f/g=3. And you are correct there are no domain restrictions.

Domain restrictions are only possible when you have

1) A denominator that contains the x, and whatever x-value that makes the denominator equal zero, can not be the domain.
(because anything/zero = undefined

2) A square or even root of a negative number is NOT a real number, so if you have

\(\LARGE\color{red}{ \bf g(x)= \sqrt[even]{number~-~x} }\)

x has to be a value that makes the square root be NOT LESS THAN zero.
(or it will be an imaginary number)