Question

8x^-3y^-1
over
-2x^6y^-4

Answer 1

its -(4 x^3)/y^5 or (-4 x^3)/y^5

Answer 2

\[\large \frac{8x^{-3}y^{-1}}{-2x^6y^{-4}}\]

Answer 3

−4x^−3y−6y4− that is what I got.?

Answer 4

If we use the rule for dividing exponents with the same base...we just subtract the exponents...so we have

in terms of the 'x' term....we have\[\large \frac{x^{-3}}{x^6} = x^{-3 - 6} = x^{-9}\]

and now interms of the 'y' we have \[\large \frac{y^{-1}}{y^{-4}} = y^{-1 - (-4)} = y^{-1 + 4} = y^{3}\]

so we have

\[\large -4x^{-9}y^{3}\] or written as \[\large \frac{-4y^3}{x^9}\]

Answer 5

ill try it

Answer 6

I WAS RIGHT!!!!!!! WOHOOO LOL anyhow thx john