Question

For the function f(x) = (8-2x)2 @kelliegirl33

Answer 1

@OrangeMaster

Answer 2

we have given that f(x)=(8-2x)^2
first we have to take f(x)= y

so we get y = (8-2x)^2

to solve this for x we have to take square root of both sides.

we get for that is +-\[\sqrt{y}\] = (8-2x)

to get rid of 8 from right side we have to add -8 to both sides
so we get +-\[\sqrt{y}\] -8 = -2x
to get rid of -2 from right side we have to divide it by both sides.

so we get +-\[\frac{ \sqrt{y}-8 }{ -2 }\]

then

\[\frac{ 8+-\sqrt{y} }{ 2}\]

now change y by x we get \[\frac{ 8+-\sqrt{x} }{ 2}\]

this is final answer. which is inverse of the given function.