Question

I need help with graphing rational functions :)

Answer 1

e

Answer 2

Isn't it more than one?

Answer 3

no !

Answer 4

It was 2 and 0...

Answer 5

Could someone help me with this?

Answer 6

From the graph you can see the function is undefined or discontinuous at x = -3. That happens when the denominator of a rational function goes to zero at x = -3.
So the denominator must be (x+3).

Answer 7

Can someone please help me?

Answer 8

zeros of a function are the values of the independent variable that make the function equal to zero. For a rational expression like you have, the values that make the numerator equal to zero are the values that make the entire expression equal to zero, because 0 divided by anything (except 0) is always 0, and the only way you can get 0 as a quotient is by dividing 0 by some other number.

Values of the independent variable that make the denominator equal to zero, on the other hand, are called restricted values, because we are not allowed to divide by 0 (there not being any sensible result to doing so). So, to find the zeros, look at the numerator and set each product term equal to 0 and solve for the value(s) of the independent variable. Then make sure that none of those values also make the denominator equal to 0. Any value which makes the numerator equal to 0 but does not also make the denominator equal to 0 is a zero of the expression.