Question

FAN & MEDAL
Multiply. The equation in the attachment below its a rational equation XD

Answer 1

@surjithayer

Answer 2

make factors of
1.x^2+8x+15
2. x^2-16
take common 2 out of 2x+6
then cancel if you can.

Answer 3

ok so what do i cancel out

Answer 4

first make factors then you will come to know.

Answer 5

ok

Answer 6

do i make the 2 a negative2

Answer 7

no,make factors of\[x^2+8x+15\]

Answer 8

ok

Answer 9

wouldn't that be 3

Answer 10

\[x^2+8x+15=x^2+5x+3x+15=x \left( ? \right)+3\left( ? \right) \]

Answer 11

ok what do i plug in at the ?? marks

Answer 12

i think you don't know ,how to make factors?

Answer 13

yes i do

Answer 14

ain't it 3

Answer 15

can u tell me the answer thoe

Answer 16

\[x^2+5 x+3 x+15=x \left( x+5 \right)+3\left( x+5 \right)=\left( x+5 \right)\left( x+3 \right)\]

Answer 17

\[x^2-16=x^2-4^2=\left( x+4 \right)\left( x-4 \right)\]

Answer 18

ok hold on let me check the answer choices k

Answer 19

2x+6=2(x+3)

Answer 20

is that the answer

Answer 21

now write down these factors and see which of these you can cancel.

Answer 22

ok

Answer 23

the x and 3

Answer 24

@surjithayer

Answer 25

im going to come back to this question k jus tag my name after u post ur comment k

Answer 26

\[\frac{ x^2+8x+15 }{ x-4 }\times \frac{ x^2-16 }{ 2x+6 }=\frac{ \left( x+5 \right) \left( x+3 \right)}{ x-4 } \times\frac{ \left( x+4 \right) \left( x-4 \right)}{ 2\left( x+3 \right) }\]
\[=\frac{ \left( x+5 \right) \left( x+4 \right)}{ 2 }=\frac{ x^2+5x+4x+20 }{ 2 }=?\]

Answer 27

well thanx for ur help but i got the answer now

Answer 28

yw